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Linear Equations Word Problems (Class 10): How to Form a Pair of Linear Equations

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Linear Equations Word Problems (Class 10): How to Form a Pair of Linear Equations

In one line: to form a pair of linear equations from a word problem, name the two unknowns as x and y, then turn each stated fact into one linear equation — two facts give you the two equations of the pair.

Every word problem in Chapter 3 hides the same structure: a situation with two unknown quantities and two conditions connecting them. Your job is translation — converting each condition from English into algebra. Once the pair of linear equations is written correctly, the hard part is done; solving is mechanical.

This article gives you a reliable 4-step method, a phrase-to-maths translation table, and worked examples of the problem types that appear again and again. It builds directly on what a pair of linear equations means, so read that first if the term is new.

▶️ Watch the 30-second reel: Can you spot the right equation? 👀

The 4-step method to form a pair of linear equations

Step 1 — Identify the two unknowns. Read the question part first (“find the number of…”, “find the cost of…”). The two things being asked for are your unknowns.

Step 2 — Assign variables in words. Write “Let the number of pencils be x” and “Let the number of erasers be y” — in words, with units. In board answers this defining line earns credit on its own, as the marking-style guide explains.

Step 3 — Translate each condition into one equation. Go sentence by sentence. Each independent fact (a total, a comparison, a relationship) becomes exactly one linear equation.

Step 4 — Check the pair. Confirm each equation is linear (powers of x and y are 1), that you used both facts, and that units match on both sides. You now have a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 — a pair of linear equations representing the situation.

A memory hook for the four steps: I–A–T–C — “Identify, Assign, Translate, Check.”

Translation table: common phrases → equations

Phrase in the problem Becomes Example
“sum of the two numbers is 27” x + y = 27
“x is 4 more than y” x = y + 4 girls are 4 more than boys
“x is 3 less than y” x = y − 3
“twice / double y” 2y x = 2y
“total cost” price × quantity, added 12x + 20y = 88
“difference of the numbers is 3” x − y = 3 (larger − smaller)
“three times as old as” x = 3y father and son

Keep this table handy while practising — after a few problems the translations become automatic. The Practice Companion on examfront drills exactly this phrase-by-phrase skill and flags the specific phrase types you mistranslate.

Worked example 1 — cost problem

5 pencils and 3 erasers together cost ₹31, while 2 pencils and 4 erasers together cost ₹18. Represent this situation as a pair of linear equations.

  • Identify: the unknowns are the cost of one pencil and the cost of one eraser.
  • Assign: let the cost of one pencil be ₹x and the cost of one eraser be ₹y.
  • Translate: first fact → 5x + 3y = 31; second fact → 2x + 4y = 18.
  • Check: both linear, both facts used, both sides in rupees. ✓

The pair is 5x + 3y = 31 and 2x + 4y = 18. (You can verify that x = 5, y = 2 satisfies both: 25 + 6 = 31 ✓ and 10 + 8 = 18 ✓ — so a pencil costs ₹5 and an eraser ₹2.)

▶️ Watch the 30-second reel: Can you build the bill equation? 🥟

Worked example 2 — comparison / count problem

A class has 42 students, and the number of girls is 6 more than the number of boys. Represent this as a pair of linear equations.

  • Assign: let the number of boys be x and the number of girls be y.
  • Translate: “42 students in total” → x + y = 42; “girls are 6 more than boys” → y = x + 6.
  • Check: two linear equations, both facts used. ✓

The pair is x + y = 42 and y = x + 6. Checking x = 18, y = 24 satisfies both, so the class has 18 boys and 24 girls.

▶️ Watch the 30-second reel: Can you set up the two equations? 🤔

Worked example 3 — age problem

A father is three times as old as his son, and the sum of their ages is 48 years. Represent this as a pair of linear equations.

  • Assign: let the father’s present age be x years and the son’s present age be y years.
  • Translate: “three times as old” → x = 3y; “sum of ages is 48” → x + y = 48.
  • Check: both linear. ✓ The pair is x = 3y and x + y = 48 (father 36, son 12 satisfies both).

▶️ Watch the 30-second reel: Can you spot the age equation? 👀

These three patterns — cost, count-comparison and simple ages — cover the friendly end of the spectrum. The tougher variations (ages “5 years ago / 3 years hence”, two-digit numbers with reversed digits, fractions that change when numerator and denominator are altered, speed–distance setups) use the same I–A–T–C method but need more careful translation. That full set, with graded difficulty and step-by-step feedback, is inside examfront’s Topic Practice — and the Strength & Weakness Analysis tells you which problem type to drill next. Word-problem setups also appear as case-study questions in the board pattern, so this skill pays off in more than one section of the paper.

▶️ Watch the 30-second reel: Can you spot the correct ticket equations? 🎟️

Board answer format: the marks-safe way to write it

For a “represent the situation” question, write these lines in order:

  1. Let statement: “Let the number of … be x and the number of … be y.”
  2. Equation 1 with a one-phrase reason: “Since the total is 42: x + y = 42.”
  3. Equation 2 with its reason: “Since girls are 6 more than boys: y = x + 6.”
  4. (If asked to solve) the solution and a verification line checking the answer against the original story.

Skipping the “Let” line or the verification is one of the classic ways students lose easy marks — the maths is right but the presentation leaks marks.

Key Takeaways

  • A word problem with two unknowns and two conditions always yields a pair of linear equations.
  • Follow I–A–T–C: Identify unknowns → Assign variables in words → Translate each condition into one equation → Check the pair.
  • Each independent fact becomes exactly one equation; you need both.
  • Always write the “Let x = …, y = …” line — it defines your equations and carries marks.
  • Verify any solution against the original story, not just the equations.

Quick Facts

  • Unknowns per problem: 2 → variables x and y.
  • Conditions per problem: 2 → one equation each.
  • Method: I–A–T–C (Identify, Assign, Translate, Check).
  • “4 more than y”: y + 4 · “twice x”: 2x · “total cost”: price × quantity summed.
  • Common types: cost problems, count comparisons, age problems (harder: digits, fractions, speed–distance).
  • Chapter: Pair of Linear Equations in Two Variables (Ch. 3) · Class: 10 · Subject: Maths · Board: CBSE.

Common Mistakes

  1. Not defining the variables. Jumping straight to equations without “Let x = …” — the equations become ambiguous and the defining mark is lost.
  2. Reversing a comparison. “Girls are 6 more than boys” is y = x + 6, not x = y + 6. Read who has more, then add 6 to the smaller side.
  3. Cramming both facts into one equation. Each condition is its own equation; merging them (or using only one) leaves the pair incomplete.
  4. Mixing units. Putting rupees on one side and counts on the other, or ages with totals of money. Both sides of an equation must measure the same thing.
  5. Verifying against the equations only. A calculation slip can satisfy your (wrong) equations. Always check the final answer against the original sentences of the problem.

FAQ

Q. How do you form a pair of linear equations from a word problem? Identify the two unknowns, assign x and y to them in words, translate each stated condition into one linear equation, and check that both equations are linear and both facts are used. The two equations are your pair.

Q. How do I decide what x and y should be? Choose the two quantities the question asks you to find, and write them out: “Let the number of … be x.” Defining variables in words first keeps the translation honest and earns presentation marks.

Q. How many equations do I need for two unknowns? Two independent equations. One equation in two variables has infinitely many solutions, so a single condition can never determine both unknowns.

Q. What does “twice as many” or “6 more than” become in an equation? “x is twice y” → x = 2y. “y is 6 more than x” → y = x + 6. Translate one phrase at a time using a small phrase-to-maths table until it is automatic.

Q. Do I also have to solve the equations? For Section 3.1, representing the situation is the skill. In full board questions you usually solve the pair too — graphically or algebraically — and then verify the answer against the story.


Want the harder problem types — digits, fractions, ages with time shifts? Work the full graded set with Mistake Identification on examfront, and let your Personalized Learning Path queue the next drill. Start on examfront →

Frequently asked

How do you form a pair of linear equations from a word problem?

Use four steps: (1) read and identify the two unknown quantities, (2) assign a variable to each (let x = …, let y = …), (3) translate each stated condition into one linear equation, (4) check both equations are linear and use both facts. Two conditions give you the pair.

How do I know what to take as x and y in a word problem?

Take the two quantities the question actually asks you to find. Write 'Let x = number of …' and 'Let y = number of …' with units, in words, before writing any equation — this line also carries marks in board answers.

How many equations do I need for a word problem with two unknowns?

Two independent equations — one for each condition given in the problem. One equation alone has infinitely many solutions, so it cannot determine two unknowns.

What do phrases like 'twice', 'more than' and 'total cost' become in equations?

'Twice y' becomes 2y, 'x is 4 more than y' becomes x = y + 4, and 'total cost' becomes (price × quantity) added across items, e.g. 12x + 20y = 88. Translate one phrase at a time.

Do I have to solve the equations too, or just form them?

In Section 3.1 the skill is forming and representing. In the rest of Chapter 3 (and in board questions) you usually solve the pair as well — graphically or by substitution or elimination — and then verify the answer against the original problem.

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