examfront · Learning Hub

Learning Hub /NCERT Learning Guides /Surface Area of a Combination of Solids Class 10: Method & Examples

Surface Area of a Combination of Solids Class 10: Method & Examples

NCERT Learning Guides

Surface Area of a Combination of Solids Class 10: Method & Examples

Quick answer: To find the surface area of a combination of solids, add together only the surfaces that stay exposed after the pieces are joined. When two solids are stuck together, the faces that touch are hidden inside the join and are not counted. So the total surface area of a combined solid is always less than the sum of the two solids’ separate surface areas.

A combination of solids is an object made by joining two or more basic solids — a cone, cylinder, sphere, hemisphere, cuboid or cube. Real objects work like this: a test tube is a cylinder plus a hemisphere; a toy top is a cone plus a hemisphere; a truck’s oil container is a cylinder with two hemispherical ends.

This guide gives you one reliable method and worked examples for the exam. It assumes you already know the basic-solid formulas — if you need them, start with the surface area and volume formulas guide. For the harder composite figures (tents, capsules, hollowed cylinders) and full practice, you can go deeper on examfront.

The one rule: add only the exposed surfaces

When you glue two solids together, the two faces that meet disappear from the outside. They are still there, but they are now inside the object, so no paint could ever reach them.

The rule: Surface area of a combined solid = sum of the exposed (visible) surface areas of each part. Never add the hidden faces at the join.

This is why combined-solid problems almost always use Curved Surface Area (CSA). Example: a toy is a cone sitting on a hemisphere. The only surfaces you can see and paint are the curved surface of the cone and the curved surface of the hemisphere. The flat circle where they meet is hidden. So:

Total surface area of the toy = CSA of the cone + CSA of the hemisphere

You do not add the cone’s base or the hemisphere’s flat face — those are the hidden join.

A step-by-step method you can trust

For any surface-area-of-combination problem:

  1. Identify the basic solids that make up the object (cone, cylinder, hemisphere, cube …).
  2. Decide which faces are exposed — picture painting the object; only painted faces count.
  3. Write the surface area as a sum of those exposed pieces (usually CSAs, plus any leftover flat area).
  4. For a cavity or depression, subtract the flat area it replaces (πr²) and add the curved area it creates (2πr² for a hemisphere).
  5. Substitute the values, keep units square (cm²), and compute.

Worked example 1: a toy (cone on a hemisphere)

Problem. A toy is in the shape of a cone standing on a hemisphere. Both have radius 7 cm, and the cone’s slant height is 25 cm. Find the surface area of the toy. (Use π = 22/7.)

Solution. The exposed surfaces are the curved surface of the hemisphere and the curved surface of the cone.

  • CSA of hemisphere = 2πr² = 2 × (22/7) × 7² = 2 × 22 × 7 = 308 cm²
  • CSA of cone = πrl = (22/7) × 7 × 25 = 22 × 25 = 550 cm²
  • Surface area of toy = 308 + 550 = 858 cm²

Notice we never used the flat faces — the circle where the cone meets the hemisphere is hidden inside the join.

Want to see this with different radii and slant heights until it clicks? examfront’s Topic Practice serves cone-and-hemisphere variations with instant checking.

🎬 Quick challenge: Can you spot what happens to surface area when two solids join?

Worked example 2: a cube with a hemisphere on top

Problem. A wooden block is a cube of edge 7 cm with a hemisphere of the greatest possible diameter fixed on one face. Find the surface area of the solid. (Use π = 22/7.)

Solution. The greatest diameter equals the cube’s edge, so the hemisphere’s diameter = 7 cm and its radius r = 3.5 cm.

The surface = all 6 cube faces, minus the circle the hemisphere covers, plus the hemisphere’s curved surface:

  • TSA of cube = 6 = 6 × 7² = 294 cm²
  • Circle covered by the hemisphere = πr² = (22/7) × 3.5² = 38.5 cm² (subtract)
  • CSA of hemisphere = 2πr² = 2 × 38.5 = 77 cm² (add)
  • Surface area = 294 − 38.5 + 77 = 332.5 cm²

Because we subtract one πr² and add two πr², this neatly simplifies to 6a² + πr² — a handy shortcut for “hemisphere on a cube.”

Depression vs. bump: whether the hemisphere is scooped into the face (a depression) or sits on it (a bump), the surface-area change is the same — remove the flat circle (πr²), add the curved surface (2πr²). Only the volume changes between the two cases.

What’s reserved for deeper practice

The exam also asks these harder combinations: a tent (cylinder + cone, base not covered), a medicine capsule (cylinder + two hemispheres), a cylinder with a conical cavity hollowed out, and articles made by scooping a hemisphere from each end of a cylinder. Each uses the exact same rule — count only the exposed surfaces — but with more pieces to track.

Work the full set of these composite-figure problems, step by step, inside examfront’s Chapter Quizzes, and use Mistake Identification to catch the exact face you keep forgetting to add or subtract.

🎬 Quick challenge: Can you find the surface area of this cone-and-hemisphere toy? 🪀

Key Takeaways

  • Surface area of a combined solid = sum of the exposed surfaces only; joined faces are hidden.
  • The combined surface area is always less than the sum of the two separate surface areas.
  • Combined problems mostly use CSA of each part (πrl for cone, 2πr² for hemisphere, 2πrh for cylinder).
  • For a cavity or depression: subtract the flat circle (πr²), add the curved surface (2πr²).
  • “Hemisphere on a cube” shortcut: surface area = 6a² + πr².

Quick Facts

  • CSA of cone = πrl; CSA of hemisphere = 2πr²; CSA of cylinder = 2πrh.
  • Toy (cone on hemisphere): surface area = 2πr² + πrl.
  • A hemispherical depression changes surface area by +πr² overall (−πr² flat, +2πr² curved).
  • Surface area is always in square units (cm², m²).
  • The flat face at a join is never part of the surface area.

Common Mistakes

  1. Adding both solids’ full TSAs — this double-counts the hidden join; add only exposed surfaces.
  2. Including the flat face at the join — that face is inside the solid, not on the surface.
  3. Forgetting to subtract the base circle for a depression — remove πr² before adding 2πr².
  4. Using the cone’s vertical height instead of slant height — CSA needs l = √(r²+h²).
  5. Leaving the answer in cm instead of cm² — surface area is a squared unit.

FAQ

How do you find the surface area of a combination of solids in Class 10? Add only the surfaces that stay exposed after joining. Hidden faces at the join are not counted. For a cone on a hemisphere, surface area = CSA of cone + CSA of hemisphere = πrl + 2πr².

Why is the surface area of a combined solid not equal to the sum of the two solids’ surface areas? Because the two faces that touch when joined are hidden inside the object. Adding both full surface areas would count these hidden faces, so the true combined surface area is always less than the simple sum.

What is the surface area of a toy that is a cone on a hemisphere? For a cone on a hemisphere of the same radius r, surface area = 2πr² + πrl, where l is the cone’s slant height. The flat faces where they meet are hidden and not counted.

How do you handle a hemispherical depression or cavity when finding surface area? Remove the flat circle it covers (πr²) and add the curved surface it creates (2πr²). A cube with a hemisphere on one face has surface area = 6a² − πr² + 2πr² = 6a² + πr².

Do you use total surface area or curved surface area for combined solids? Mostly curved surface area (CSA) of each exposed part, plus any flat face that stays visible. Any flat face hidden at the join is left out.

  • Surface Area and Volume Formulas (12.1) — the six basic-solid formulas this method combines; see the formula sheet.
  • Volume of a Combination of Solids (12.3) — where volumes simply add up; see the volume of a combination guide.
  • Area of Sector and Segment of a Circle (Chapter 11) — the circle-area foundation for πr² faces; see the area of sector and segment guide.
  • Class 10 Maths All Formulas — the complete cross-chapter formula reference.

Ready to test yourself? Start with examfront’s Surface Areas and Volumes quiz, track which combined shapes trip you up with Progress Tracking, and get personalised help exactly where you slip.

Frequently asked

How do you find the surface area of a combination of solids in Class 10?

Add together only the surfaces that stay exposed after the solids are joined. When two solids are stuck together, the faces that touch are hidden and are not counted. So for a toy made of a cone on a hemisphere, the surface area = CSA of the cone + CSA of the hemisphere. You do not add the flat faces where they join.

Why is the surface area of a combined solid not equal to the sum of the two solids' surface areas?

Because the two faces that come into contact when the solids are joined are no longer on the outside — they are hidden inside the join. Adding both solids' full surface areas would count these hidden faces, which are not part of the new outer surface. So the combined surface area is always less than the simple sum.

What is the surface area of a toy that is a cone on a hemisphere?

For a toy formed by a cone standing on a hemisphere of the same radius r, the total surface area = CSA of the hemisphere + CSA of the cone = 2πr² + πrl, where l is the slant height of the cone. The flat circular faces where the cone meets the hemisphere are inside the join, so they are not counted.

How do you handle a hemispherical depression or cavity when finding surface area?

When a hemisphere is scooped out of (or bulges from) a flat face, remove the flat circular area it covers (πr²) and add the curved surface it creates (2πr²). For example, a cube with a hemisphere on one face has surface area = 6a² − πr² + 2πr² = 6a² + πr².

Do you use total surface area or curved surface area for combined solids?

Use the curved surface area (CSA) of each part that is exposed, and add any flat faces that remain visible. You leave out any flat face that is hidden at the join. This is why combined-solid problems mostly use CSA, not the full TSA of each piece.

Related resources

Turn this into a study plan

examfront builds it around your weak areas.

Start free ->